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-5x^2+960x-14400=0
a = -5; b = 960; c = -14400;
Δ = b2-4ac
Δ = 9602-4·(-5)·(-14400)
Δ = 633600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{633600}=\sqrt{57600*11}=\sqrt{57600}*\sqrt{11}=240\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(960)-240\sqrt{11}}{2*-5}=\frac{-960-240\sqrt{11}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(960)+240\sqrt{11}}{2*-5}=\frac{-960+240\sqrt{11}}{-10} $
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